2+x-[x-(x-1)]+(x+2)=256

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Solution for 2+x-[x-(x-1)]+(x+2)=256 equation:


Simplifying
2 + x + -1[x + -1(x + -1)] + (x + 2) = 256

Reorder the terms:
2 + x + -1[x + -1(-1 + x)] + (x + 2) = 256
2 + x + -1[x + (-1 * -1 + x * -1)] + (x + 2) = 256
2 + x + -1[x + (1 + -1x)] + (x + 2) = 256

Reorder the terms:
2 + x + -1[1 + x + -1x] + (x + 2) = 256

Combine like terms: x + -1x = 0
2 + x + -1[1 + 0] + (x + 2) = 256
2 + x + -1[1] + (x + 2) = 256

Multiply -1 * 1
2 + x + -1 + (x + 2) = 256

Reorder the terms:
2 + x + -1 + (2 + x) = 256

Remove parenthesis around (2 + x)
2 + x + -1 + 2 + x = 256

Reorder the terms:
2 + -1 + 2 + x + x = 256

Combine like terms: 2 + -1 = 1
1 + 2 + x + x = 256

Combine like terms: 1 + 2 = 3
3 + x + x = 256

Combine like terms: x + x = 2x
3 + 2x = 256

Solving
3 + 2x = 256

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2x = 256 + -3

Combine like terms: 3 + -3 = 0
0 + 2x = 256 + -3
2x = 256 + -3

Combine like terms: 256 + -3 = 253
2x = 253

Divide each side by '2'.
x = 126.5

Simplifying
x = 126.5

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